Base | Representation |
---|---|
bin | 1011111100010101101001… |
… | …0011101101011100110101 |
3 | 1201111100000000011101000221 |
4 | 2333011122103231130311 |
5 | 3210120224403441323 |
6 | 43532223121534341 |
7 | 2523462060365353 |
oct | 277053223553465 |
9 | 51440000141027 |
10 | 13131230140213 |
11 | 4202a180a1429 |
12 | 1580b064a43b1 |
13 | 743367678163 |
14 | 3357aaa287d3 |
15 | 17b8904db55d |
hex | bf15a4ed735 |
13131230140213 has 2 divisors, whose sum is σ = 13131230140214. Its totient is φ = 13131230140212.
The previous prime is 13131230140207. The next prime is 13131230140247. The reversal of 13131230140213 is 31204103213131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10349616594724 + 2781613545489 = 3217082^2 + 1667817^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13131230140213 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13131230146213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565615070106 + 6565615070107.
It is an arithmetic number, because the mean of its divisors is an integer number (6565615070107).
Almost surely, 213131230140213 is an apocalyptic number.
It is an amenable number.
13131230140213 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131230140213 is an equidigital number, since it uses as much as digits as its factorization.
13131230140213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13131230140213 its reverse (31204103213131), we get a palindrome (44335333353344).
The spelling of 13131230140213 in words is "thirteen trillion, one hundred thirty-one billion, two hundred thirty million, one hundred forty thousand, two hundred thirteen".
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