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13131230140213 is a prime number
BaseRepresentation
bin1011111100010101101001…
…0011101101011100110101
31201111100000000011101000221
42333011122103231130311
53210120224403441323
643532223121534341
72523462060365353
oct277053223553465
951440000141027
1013131230140213
114202a180a1429
121580b064a43b1
13743367678163
143357aaa287d3
1517b8904db55d
hexbf15a4ed735

13131230140213 has 2 divisors, whose sum is σ = 13131230140214. Its totient is φ = 13131230140212.

The previous prime is 13131230140207. The next prime is 13131230140247. The reversal of 13131230140213 is 31204103213131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10349616594724 + 2781613545489 = 3217082^2 + 1667817^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13131230140213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13131230146213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565615070106 + 6565615070107.

It is an arithmetic number, because the mean of its divisors is an integer number (6565615070107).

Almost surely, 213131230140213 is an apocalyptic number.

It is an amenable number.

13131230140213 is a deficient number, since it is larger than the sum of its proper divisors (1).

13131230140213 is an equidigital number, since it uses as much as digits as its factorization.

13131230140213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13131230140213 its reverse (31204103213131), we get a palindrome (44335333353344).

The spelling of 13131230140213 in words is "thirteen trillion, one hundred thirty-one billion, two hundred thirty million, one hundred forty thousand, two hundred thirteen".