Base | Representation |
---|---|
bin | 1011111100010101101001… |
… | …0011101101011101010111 |
3 | 1201111100000000011101002012 |
4 | 2333011122103231131113 |
5 | 3210120224403441442 |
6 | 43532223121534435 |
7 | 2523462060365432 |
oct | 277053223553527 |
9 | 51440000141065 |
10 | 13131230140247 |
11 | 4202a180a145a |
12 | 1580b064a441b |
13 | 74336767818b |
14 | 3357aaa28819 |
15 | 17b8904db582 |
hex | bf15a4ed757 |
13131230140247 has 2 divisors, whose sum is σ = 13131230140248. Its totient is φ = 13131230140246.
The previous prime is 13131230140213. The next prime is 13131230140277. The reversal of 13131230140247 is 74204103213131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13131230140247 - 26 = 13131230140183 is a prime.
It is a super-2 number, since 2×131312301402472 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13131230140207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565615070123 + 6565615070124.
It is an arithmetic number, because the mean of its divisors is an integer number (6565615070124).
Almost surely, 213131230140247 is an apocalyptic number.
13131230140247 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131230140247 is an equidigital number, since it uses as much as digits as its factorization.
13131230140247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 32.
Adding to 13131230140247 its reverse (74204103213131), we get a palindrome (87335333353378).
The spelling of 13131230140247 in words is "thirteen trillion, one hundred thirty-one billion, two hundred thirty million, one hundred forty thousand, two hundred forty-seven".
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