Base | Representation |
---|---|
bin | 111101001001011010… |
… | …0101101011111001111 |
3 | 110112221101021111211011 |
4 | 1322102310231133033 |
5 | 4122411422411343 |
6 | 140153554310051 |
7 | 12326020135453 |
oct | 1722264553717 |
9 | 415841244734 |
10 | 131312310223 |
11 | 50764415236 |
12 | 21548288327 |
13 | c4c8a2ca63 |
14 | 64d98b2663 |
15 | 363818629d |
hex | 1e92d2d7cf |
131312310223 has 2 divisors, whose sum is σ = 131312310224. Its totient is φ = 131312310222.
The previous prime is 131312310211. The next prime is 131312310257. The reversal of 131312310223 is 322013213131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131312310223 - 217 = 131312179151 is a prime.
It is a super-2 number, since 2×1313123102232 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131312310194 and 131312310203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131312310293) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65656155111 + 65656155112.
It is an arithmetic number, because the mean of its divisors is an integer number (65656155112).
Almost surely, 2131312310223 is an apocalyptic number.
131312310223 is a deficient number, since it is larger than the sum of its proper divisors (1).
131312310223 is an equidigital number, since it uses as much as digits as its factorization.
131312310223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 131312310223 its reverse (322013213131), we get a palindrome (453325523354).
The spelling of 131312310223 in words is "one hundred thirty-one billion, three hundred twelve million, three hundred ten thousand, two hundred twenty-three".
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