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131313110003 = 1213108254831
BaseRepresentation
bin111101001001011011…
…1110000101111110011
3110112221102210010220122
41322102313300233303
54122412124010003
6140154023400455
712326030006255
oct1722267605763
9415842703818
10131313110003
1150764911109
12215485b312b
13c4c8c4caba
1464d9a3dcd5
153638293238
hex1e92df0bf3

131313110003 has 4 divisors (see below), whose sum is σ = 131421366048. Its totient is φ = 131204853960.

The previous prime is 131313109969. The next prime is 131313110011. The reversal of 131313110003 is 300011313131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131313110003 - 28 = 131313109747 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131313110053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54126203 + ... + 54128628.

It is an arithmetic number, because the mean of its divisors is an integer number (32855341512).

Almost surely, 2131313110003 is an apocalyptic number.

131313110003 is a deficient number, since it is larger than the sum of its proper divisors (108256045).

131313110003 is a wasteful number, since it uses less digits than its factorization.

131313110003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 108256044.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 131313110003 its reverse (300011313131), we get a palindrome (431324423134).

The spelling of 131313110003 in words is "one hundred thirty-one billion, three hundred thirteen million, one hundred ten thousand, three".

Divisors: 1 1213 108254831 131313110003