Base | Representation |
---|---|
bin | 1011111100010110011100… |
… | …0100110010000000111000 |
3 | 1201111100112221012100221110 |
4 | 2333011213010302000320 |
5 | 3210121144222034202 |
6 | 43532300252440320 |
7 | 2523500301104112 |
oct | 277054704620070 |
9 | 51440487170843 |
10 | 13131444330552 |
11 | 4203017a96839 |
12 | 1580b661790a0 |
13 | 74339cb603c2 |
14 | 3357cb2623b2 |
15 | 17b8a41ea26c |
hex | bf167132038 |
13131444330552 has 64 divisors (see below), whose sum is σ = 32843832516000. Its totient is φ = 4375119020544.
The previous prime is 13131444330491. The next prime is 13131444330553. The reversal of 13131444330552 is 25503344413131.
It is a self number, because there is not a number n which added to its sum of digits gives 13131444330552.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13131444330553) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 949551574 + ... + 949565402.
Almost surely, 213131444330552 is an apocalyptic number.
13131444330552 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13131444330552 is an abundant number, since it is smaller than the sum of its proper divisors (19712388185448).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13131444330552 is a wasteful number, since it uses less digits than its factorization.
13131444330552 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29320 (or 29316 counting only the distinct ones).
The product of its (nonzero) digits is 259200, while the sum is 39.
Adding to 13131444330552 its reverse (25503344413131), we get a palindrome (38634788743683).
The spelling of 13131444330552 in words is "thirteen trillion, one hundred thirty-one billion, four hundred forty-four million, three hundred thirty thousand, five hundred fifty-two".
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