Base | Representation |
---|---|
bin | 1011111100010111001111… |
… | …1010101010111011110111 |
3 | 1201111101002221121112102002 |
4 | 2333011303322222323313 |
5 | 3210122114401041202 |
6 | 43532333510405515 |
7 | 2523505525323056 |
oct | 277056372527367 |
9 | 51441087545362 |
10 | 13131659783927 |
11 | 4203118674083 |
12 | 158100636089b |
13 | 7434056984c9 |
14 | 33580bb0839d |
15 | 17b8b80a8302 |
hex | bf173eaaef7 |
13131659783927 has 2 divisors, whose sum is σ = 13131659783928. Its totient is φ = 13131659783926.
The previous prime is 13131659783917. The next prime is 13131659783929. The reversal of 13131659783927 is 72938795613131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13131659783927 - 26 = 13131659783863 is a prime.
Together with 13131659783929, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13131659783929) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565829891963 + 6565829891964.
It is an arithmetic number, because the mean of its divisors is an integer number (6565829891964).
Almost surely, 213131659783927 is an apocalyptic number.
13131659783927 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131659783927 is an equidigital number, since it uses as much as digits as its factorization.
13131659783927 is an evil number, because the sum of its binary digits is even.
The product of its digits is 51438240, while the sum is 65.
The spelling of 13131659783927 in words is "thirteen trillion, one hundred thirty-one billion, six hundred fifty-nine million, seven hundred eighty-three thousand, nine hundred twenty-seven".
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