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1313200123303 = 2647496108849
BaseRepresentation
bin10011000111000000110…
…100111010110110100111
311122112121011201012020211
4103013000310322312213
5133003413212421203
62443135324040251
7163606215606025
oct23070064726647
94575534635224
101313200123303
11466a1a264202
12192610093087
1396aaca975a3
14477b8729715
152425cc07c6d
hex131c0d3ada7

1313200123303 has 4 divisors (see below), whose sum is σ = 1313696234800. Its totient is φ = 1312704011808.

The previous prime is 1313200123289. The next prime is 1313200123307. The reversal of 1313200123303 is 3033210023131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1313200123303 - 25 = 1313200123271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313200123307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 248051778 + ... + 248057071.

It is an arithmetic number, because the mean of its divisors is an integer number (328424058700).

Almost surely, 21313200123303 is an apocalyptic number.

1313200123303 is a deficient number, since it is larger than the sum of its proper divisors (496111497).

1313200123303 is an equidigital number, since it uses as much as digits as its factorization.

1313200123303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 496111496.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 1313200123303 its reverse (3033210023131), we get a palindrome (4346410146434).

The spelling of 1313200123303 in words is "one trillion, three hundred thirteen billion, two hundred million, one hundred twenty-three thousand, three hundred three".

Divisors: 1 2647 496108849 1313200123303