1313204110403 has 4 divisors (see below), whose sum is σ = 1313654303280. Its totient is φ = 1312753917528.

The previous prime is 1313204110399. The next prime is 1313204110417. The reversal of 1313204110403 is 3040114023131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1313204110403 - 2² = 1313204110399 is a prime.

It is a super-2 number, since 2×1313204110403² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1313204110003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225092063 + ... + 225097896.

It is an arithmetic number, because the mean of its divisors is an integer number (328413575820).

Almost surely, 2^{1313204110403} is an apocalyptic number.

1313204110403 is a deficient number, since it is larger than the sum of its proper divisors (450192877).

1313204110403 is an equidigital number, since it uses as much as digits as its factorization.

1313204110403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 450192876.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 1313204110403 its reverse (3040114023131), we get a palindrome (4353318133534).

The spelling of 1313204110403 in words is "one trillion, three hundred thirteen billion, two hundred four million, one hundred ten thousand, four hundred three".