Base | Representation |
---|---|
bin | 1011111100011000101101… |
… | …0011100111101100111111 |
3 | 1201111102010022000100102011 |
4 | 2333012023103213230333 |
5 | 3210123420330402010 |
6 | 43532440445312051 |
7 | 2523521331651022 |
oct | 277061323475477 |
9 | 51442108010364 |
10 | 13132052200255 |
11 | 42032aa12a29a |
12 | 15810b5865627 |
13 | 743468a83011 |
14 | 335847c971b9 |
15 | 17b8dc76ea8a |
hex | bf18b4e7b3f |
13132052200255 has 8 divisors (see below), whose sum is σ = 16266800145024. Its totient is φ = 10166750090400.
The previous prime is 13132052200181. The next prime is 13132052200279. The reversal of 13132052200255 is 55200225023131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13132052200255 - 221 = 13132050103103 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 42361458556 + ... + 42361458865.
It is an arithmetic number, because the mean of its divisors is an integer number (2033350018128).
Almost surely, 213132052200255 is an apocalyptic number.
13132052200255 is a deficient number, since it is larger than the sum of its proper divisors (3134747944769).
13132052200255 is an equidigital number, since it uses as much as digits as its factorization.
13132052200255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 84722917457.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 13132052200255 its reverse (55200225023131), we get a palindrome (68332277223386).
The spelling of 13132052200255 in words is "thirteen trillion, one hundred thirty-two billion, fifty-two million, two hundred thousand, two hundred fifty-five".
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