Base | Representation |
---|---|
bin | 1011111100011000111011… |
… | …0001010101000110000110 |
3 | 1201111102021100101010201112 |
4 | 2333012032301111012012 |
5 | 3210124030220220011 |
6 | 43532450323125022 |
7 | 2523522635654246 |
oct | 277061661250606 |
9 | 51442240333645 |
10 | 13132110320006 |
11 | 4203329a16547 |
12 | 1581111213772 |
13 | 743477b221c2 |
14 | 3358518a5b26 |
15 | 17b8e290058b |
hex | bf18ec55186 |
13132110320006 has 8 divisors (see below), whose sum is σ = 19699022251704. Its totient is φ = 6565769569440.
The previous prime is 13132110319987. The next prime is 13132110320029. The reversal of 13132110320006 is 60002301123131.
13132110320006 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×131321103200063 (a number of 40 digits) contains 333 as substring.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142737800 + ... + 142829771.
It is an arithmetic number, because the mean of its divisors is an integer number (2462377781463).
Almost surely, 213132110320006 is an apocalyptic number.
13132110320006 is a deficient number, since it is larger than the sum of its proper divisors (6566911931698).
13132110320006 is a wasteful number, since it uses less digits than its factorization.
13132110320006 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 285590566.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 13132110320006 its reverse (60002301123131), we get a palindrome (73134411443137).
The spelling of 13132110320006 in words is "thirteen trillion, one hundred thirty-two billion, one hundred ten million, three hundred twenty thousand, six".
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