1313213111031 has 4 divisors (see below), whose sum is σ = 1750950814712. Its totient is φ = 875475407352.

The previous prime is 1313213111009. The next prime is 1313213111069. The reversal of 1313213111031 is 1301113123131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1313213111031 - 2⁵ = 1313213110999 is a prime.

It is a super-2 number, since 2×1313213111031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1313213110989 and 1313213111007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313213111131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218868851836 + ... + 218868851841.

It is an arithmetic number, because the mean of its divisors is an integer number (437737703678).

Almost surely, 2^{1313213111031} is an apocalyptic number.

1313213111031 is a deficient number, since it is larger than the sum of its proper divisors (437737703681).

1313213111031 is an equidigital number, since it uses as much as digits as its factorization.

1313213111031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437737703680.

The product of its (nonzero) digits is 162, while the sum is 21.

Adding to 1313213111031 its reverse (1301113123131), we get a palindrome (2614326234162).

The spelling of 1313213111031 in words is "one trillion, three hundred thirteen billion, two hundred thirteen million, one hundred eleven thousand, thirty-one".