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13132204031 is a prime number
BaseRepresentation
bin11000011101011110…
…11000011111111111
31020220012120002022002
430032233120133333
5203343321012111
610011032412515
7643266615062
oct141657303777
936805502262
1013132204031
115629872291
122665b4713b
1313138ac73b
148c81408d9
1551cd6863b
hex30ebd87ff

13132204031 has 2 divisors, whose sum is σ = 13132204032. Its totient is φ = 13132204030.

The previous prime is 13132203991. The next prime is 13132204061. The reversal of 13132204031 is 13040223131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13132204031 is a prime.

It is a super-2 number, since 2×131322040312 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 13132203994 and 13132204012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13132204061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566102015 + 6566102016.

It is an arithmetic number, because the mean of its divisors is an integer number (6566102016).

Almost surely, 213132204031 is an apocalyptic number.

13132204031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13132204031 is an equidigital number, since it uses as much as digits as its factorization.

13132204031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 13132204031 its reverse (13040223131), we get a palindrome (26172427162).

The spelling of 13132204031 in words is "thirteen billion, one hundred thirty-two million, two hundred four thousand, thirty-one".