13132233131 has 2 divisors, whose sum is σ = 13132233132. Its totient is φ = 13132233130.

The previous prime is 13132233089. The next prime is 13132233133. The reversal of 13132233131 is 13133223131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13132233131 - 2¹⁰ = 13132232107 is a prime.

It is a super-2 number, since 2×13132233131² (a number of 21 digits) contains 22 as substring.

Together with 13132233133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13132233097 and 13132233106.

It is not a weakly prime, because it can be changed into another prime (13132233133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566116565 + 6566116566.

It is an arithmetic number, because the mean of its divisors is an integer number (6566116566).

Almost surely, 2^13132233131 is an apocalyptic number.

13132233131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13132233131 is an equidigital number, since it uses as much as digits as its factorization.

13132233131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 972, while the sum is 23.

Adding to 13132233131 its reverse (13133223131), we get a palindrome (26265456262).

The spelling of 13132233131 in words is "thirteen billion, one hundred thirty-two million, two hundred thirty-three thousand, one hundred thirty-one".