Base | Representation |
---|---|
bin | 1011111100011001011010… |
… | …1111010111000010101111 |
3 | 1201111102121122221212120212 |
4 | 2333012112233113002233 |
5 | 3210124313432141143 |
6 | 43532511500533035 |
7 | 2523526151262302 |
oct | 277062657270257 |
9 | 51442548855525 |
10 | 13132244021423 |
11 | 420339843638a |
12 | 1581149b5117b |
13 | 743499735677 |
14 | 33586554ab39 |
15 | 17b8ee510918 |
hex | bf196bd70af |
13132244021423 has 2 divisors, whose sum is σ = 13132244021424. Its totient is φ = 13132244021422.
The previous prime is 13132244021381. The next prime is 13132244021461. The reversal of 13132244021423 is 32412044223131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13132244021423 - 26 = 13132244021359 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13132244021423.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13132244021473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566122010711 + 6566122010712.
It is an arithmetic number, because the mean of its divisors is an integer number (6566122010712).
Almost surely, 213132244021423 is an apocalyptic number.
13132244021423 is a deficient number, since it is larger than the sum of its proper divisors (1).
13132244021423 is an equidigital number, since it uses as much as digits as its factorization.
13132244021423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 13132244021423 its reverse (32412044223131), we get a palindrome (45544288244554).
The spelling of 13132244021423 in words is "thirteen trillion, one hundred thirty-two billion, two hundred forty-four million, twenty-one thousand, four hundred twenty-three".
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