Base | Representation |
---|---|
bin | 11101110111000000000101… |
… | …100000000011001011011111 |
3 | 122012222100122112010020110011 |
4 | 131313000011200003023133 |
5 | 114203044012124031312 |
6 | 1143144543051424051 |
7 | 36442526445025645 |
oct | 3567000540031337 |
9 | 565870575106404 |
10 | 131323012330207 |
11 | 3893085a970735 |
12 | 1288b343155027 |
13 | 5837926167b59 |
14 | 24600d3b25195 |
15 | 102b02d916da7 |
hex | 7770058032df |
131323012330207 has 2 divisors, whose sum is σ = 131323012330208. Its totient is φ = 131323012330206.
The previous prime is 131323012330183. The next prime is 131323012330243. The reversal of 131323012330207 is 702033210323131.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (702033210323131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131323012330207 - 239 = 130773256516319 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131323012331207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65661506165103 + 65661506165104.
It is an arithmetic number, because the mean of its divisors is an integer number (65661506165104).
Almost surely, 2131323012330207 is an apocalyptic number.
131323012330207 is a deficient number, since it is larger than the sum of its proper divisors (1).
131323012330207 is an equidigital number, since it uses as much as digits as its factorization.
131323012330207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13608, while the sum is 31.
Adding to 131323012330207 its reverse (702033210323131), we get a palindrome (833356222653338).
The spelling of 131323012330207 in words is "one hundred thirty-one trillion, three hundred twenty-three billion, twelve million, three hundred thirty thousand, two hundred seven".
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