Base | Representation |
---|---|
bin | 1011111100011010000000… |
… | …0011010010101010011110 |
3 | 1201111110000112220122222121 |
4 | 2333012200003102222132 |
5 | 3210130123430210220 |
6 | 43532535201133154 |
7 | 2523533056156000 |
oct | 277064003225236 |
9 | 51443015818877 |
10 | 13132400241310 |
11 | 4203468636729 |
12 | 158119232a1ba |
13 | 7434c2c0167c |
14 | 33587c1b4370 |
15 | 17b90d0bceaa |
hex | bf1a00d2a9e |
13132400241310 has 128 divisors (see below), whose sum is σ = 28268108870400. Its totient is φ = 4388177203200.
The previous prime is 13132400241281. The next prime is 13132400241391. The reversal of 13132400241310 is 1314200423131.
It is a super-2 number, since 2×131324002413102 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 137347720 + ... + 137443300.
It is an arithmetic number, because the mean of its divisors is an integer number (220844600550).
Almost surely, 213132400241310 is an apocalyptic number.
13132400241310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13132400241310 is an abundant number, since it is smaller than the sum of its proper divisors (15135708629090).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13132400241310 is an equidigital number, since it uses as much as digits as its factorization.
13132400241310 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 96627 (or 96613 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13132400241310 its reverse (1314200423131), we get a palindrome (14446600664441).
The spelling of 13132400241310 in words is "thirteen trillion, one hundred thirty-two billion, four hundred million, two hundred forty-one thousand, three hundred ten".
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