Base | Representation |
---|---|
bin | 10011000111000011010… |
… | …010000111010110100111 |
3 | 11122112201001020202201221 |
4 | 103013003102013112213 |
5 | 133004004240043421 |
6 | 2443143355201211 |
7 | 163610226064303 |
oct | 23070322072647 |
9 | 4575631222657 |
10 | 1313241331111 |
11 | 466a4054a246 |
12 | 192621a46207 |
13 | 96ab8494ac8 |
14 | 477bddb4d03 |
15 | 24261647841 |
hex | 131c34875a7 |
1313241331111 has 2 divisors, whose sum is σ = 1313241331112. Its totient is φ = 1313241331110.
The previous prime is 1313241331109. The next prime is 1313241331121. The reversal of 1313241331111 is 1111331423131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1313241331111 - 21 = 1313241331109 is a prime.
It is a super-2 number, since 2×13132413311112 (a number of 25 digits) contains 22 as substring.
Together with 1313241331109, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313241331121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656620665555 + 656620665556.
It is an arithmetic number, because the mean of its divisors is an integer number (656620665556).
Almost surely, 21313241331111 is an apocalyptic number.
1313241331111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313241331111 is an equidigital number, since it uses as much as digits as its factorization.
1313241331111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 648, while the sum is 25.
Adding to 1313241331111 its reverse (1111331423131), we get a palindrome (2424572754242).
The spelling of 1313241331111 in words is "one trillion, three hundred thirteen billion, two hundred forty-one million, three hundred thirty-one thousand, one hundred eleven".
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