Base | Representation |
---|---|
bin | 11000011101100100… |
… | …11011100100000011 |
3 | 1020220021001200021221 |
4 | 30032302123210003 |
5 | 203344022044021 |
6 | 10011101455511 |
7 | 643306453342 |
oct | 141662334403 |
9 | 36807050257 |
10 | 13133003011 |
11 | 562a2685a7 |
12 | 2666271597 |
13 | 1313acc2cb |
14 | 8c82abb59 |
15 | 51ce75241 |
hex | 30ec9b903 |
13133003011 has 4 divisors (see below), whose sum is σ = 13153428232. Its totient is φ = 13112577792.
The previous prime is 13133002943. The next prime is 13133003041. The reversal of 13133003011 is 11030033131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11030033131 = 13 ⋅848464087.
It is a cyclic number.
It is not a de Polignac number, because 13133003011 - 29 = 13133002499 is a prime.
It is a super-2 number, since 2×131330030112 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13133003041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10211646 + ... + 10212931.
It is an arithmetic number, because the mean of its divisors is an integer number (3288357058).
Almost surely, 213133003011 is an apocalyptic number.
13133003011 is a deficient number, since it is larger than the sum of its proper divisors (20425221).
13133003011 is an equidigital number, since it uses as much as digits as its factorization.
13133003011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20425220.
The product of its (nonzero) digits is 81, while the sum is 16.
Adding to 13133003011 its reverse (11030033131), we get a palindrome (24163036142).
The spelling of 13133003011 in words is "thirteen billion, one hundred thirty-three million, three thousand, eleven".
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