Base | Representation |
---|---|
bin | 1011111100011100010100… |
… | …0011011000010000101111 |
3 | 1201111111121211000112221112 |
4 | 2333013011003120100233 |
5 | 3210132411340134411 |
6 | 43533120534422235 |
7 | 2523554334542666 |
oct | 277070503302057 |
9 | 51444554015845 |
10 | 13133021021231 |
11 | 4203756a97891 |
12 | 158132620197b |
13 | 7435916c4677 |
14 | 3358da809ddd |
15 | 17b947842b8b |
hex | bf1c50d842f |
13133021021231 has 4 divisors (see below), whose sum is σ = 13438440114792. Its totient is φ = 12827601927672.
The previous prime is 13133021021207. The next prime is 13133021021249. The reversal of 13133021021231 is 13212012033131.
13133021021231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13133021021231 - 222 = 13133016826927 is a prime.
It is a super-2 number, since 2×131330210212312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13133021021197 and 13133021021206.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13133021026231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152709546716 + ... + 152709546801.
It is an arithmetic number, because the mean of its divisors is an integer number (3359610028698).
Almost surely, 213133021021231 is an apocalyptic number.
13133021021231 is a deficient number, since it is larger than the sum of its proper divisors (305419093561).
13133021021231 is an equidigital number, since it uses as much as digits as its factorization.
13133021021231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 305419093560.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 13133021021231 its reverse (13212012033131), we get a palindrome (26345033054362).
The spelling of 13133021021231 in words is "thirteen trillion, one hundred thirty-three billion, twenty-one million, twenty-one thousand, two hundred thirty-one".
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