Base | Representation |
---|---|
bin | 11101110111000111000001… |
… | …000001111111011100100100 |
3 | 122020000001212010001120202011 |
4 | 131313013001001333130210 |
5 | 114203204232101101000 |
6 | 1143152213310324004 |
7 | 36443212032152053 |
oct | 3567070101773444 |
9 | 566001763046664 |
10 | 131330453534500 |
11 | 38933a29273650 |
12 | 1289087b1b9604 |
13 | 58385409ab10c |
14 | 24605dc0d039a |
15 | 102b316d332ba |
hex | 7771c107f724 |
131330453534500 has 96 divisors (see below), whose sum is σ = 312904977840000. Its totient is φ = 47755887120000.
The previous prime is 131330453534473. The next prime is 131330453534503. The reversal of 131330453534500 is 5435354033131.
It is not an unprimeable number, because it can be changed into a prime (131330453534503) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 646142890 + ... + 646346110.
It is an arithmetic number, because the mean of its divisors is an integer number (3259426852500).
Almost surely, 2131330453534500 is an apocalyptic number.
131330453534500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131330453534500 is an abundant number, since it is smaller than the sum of its proper divisors (181574524305500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131330453534500 is a wasteful number, since it uses less digits than its factorization.
131330453534500 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 320750 (or 320738 counting only the distinct ones).
The product of its (nonzero) digits is 486000, while the sum is 40.
The spelling of 131330453534500 in words is "one hundred thirty-one trillion, three hundred thirty billion, four hundred fifty-three million, five hundred thirty-four thousand, five hundred".
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