Base | Representation |
---|---|
bin | 111101001001111101… |
… | …0101011111000101110 |
3 | 110112222122210110101202 |
4 | 1322103322223320232 |
5 | 4122431121404432 |
6 | 140155451405502 |
7 | 12326332065221 |
oct | 1722372537056 |
9 | 415878713352 |
10 | 131330653742 |
11 | 50773803a72 |
12 | 21552453892 |
13 | c4cc783202 |
14 | 64dc0c95b8 |
15 | 3639aab462 |
hex | 1e93eabe2e |
131330653742 has 4 divisors (see below), whose sum is σ = 196995980616. Its totient is φ = 65665326870.
The previous prime is 131330653687. The next prime is 131330653759. The reversal of 131330653742 is 247356033131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 247356033131 = 23291 ⋅10620241.
It is a super-2 number, since 2×1313306537422 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131330653696 and 131330653705.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32832663434 + ... + 32832663437.
It is an arithmetic number, because the mean of its divisors is an integer number (49248995154).
Almost surely, 2131330653742 is an apocalyptic number.
131330653742 is a deficient number, since it is larger than the sum of its proper divisors (65665326874).
131330653742 is an equidigital number, since it uses as much as digits as its factorization.
131330653742 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65665326873.
The product of its (nonzero) digits is 136080, while the sum is 38.
Adding to 131330653742 its reverse (247356033131), we get a palindrome (378686686873).
The spelling of 131330653742 in words is "one hundred thirty-one billion, three hundred thirty million, six hundred fifty-three thousand, seven hundred forty-two".
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