Base | Representation |
---|---|
bin | 111101001001111110… |
… | …0011000111010001101 |
3 | 110112222200122010221222 |
4 | 1322103330120322031 |
5 | 4122431230202201 |
6 | 140155505133125 |
7 | 12326335635152 |
oct | 1722374307215 |
9 | 415880563858 |
10 | 131331100301 |
11 | 50773a89525 |
12 | 2155262a1a5 |
13 | c4cc8ab54b |
14 | 64dc1a4229 |
15 | 3639b4891b |
hex | 1e93f18e8d |
131331100301 has 2 divisors, whose sum is σ = 131331100302. Its totient is φ = 131331100300.
The previous prime is 131331100261. The next prime is 131331100309. The reversal of 131331100301 is 103001133131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 97787544100 + 33543556201 = 312710^2 + 183149^2 .
It is a cyclic number.
It is not a de Polignac number, because 131331100301 - 26 = 131331100237 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131331100301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131331100309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65665550150 + 65665550151.
It is an arithmetic number, because the mean of its divisors is an integer number (65665550151).
Almost surely, 2131331100301 is an apocalyptic number.
It is an amenable number.
131331100301 is a deficient number, since it is larger than the sum of its proper divisors (1).
131331100301 is an equidigital number, since it uses as much as digits as its factorization.
131331100301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 131331100301 its reverse (103001133131), we get a palindrome (234332233432).
The spelling of 131331100301 in words is "one hundred thirty-one billion, three hundred thirty-one million, one hundred thousand, three hundred one".
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