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1313311030111 = 2515232314861
BaseRepresentation
bin10011000111000111011…
…011111111101101011111
311122112212220101211210101
4103013013123333231133
5133004130110430421
62443154325121531
7163612033365343
oct23070733775537
94575786354711
101313311030111
11466a76925123
121926412592a7
1396ac9a59612
14477c9359623
1524267814191
hex131c76ffb5f

1313311030111 has 4 divisors (see below), whose sum is σ = 1318543345224. Its totient is φ = 1308078715000.

The previous prime is 1313311030103. The next prime is 1313311030117. The reversal of 1313311030111 is 1110301133131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1313311030111 - 23 = 1313311030103 is a prime.

It is a super-2 number, since 2×13133110301112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313311030117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2616157180 + ... + 2616157681.

It is an arithmetic number, because the mean of its divisors is an integer number (329635836306).

Almost surely, 21313311030111 is an apocalyptic number.

1313311030111 is a deficient number, since it is larger than the sum of its proper divisors (5232315113).

1313311030111 is an equidigital number, since it uses as much as digits as its factorization.

1313311030111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5232315112.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 1313311030111 its reverse (1110301133131), we get a palindrome (2423612163242).

The spelling of 1313311030111 in words is "one trillion, three hundred thirteen billion, three hundred eleven million, thirty thousand, one hundred eleven".

Divisors: 1 251 5232314861 1313311030111