1313313110301 has 4 divisors (see below), whose sum is σ = 1751084147072. Its totient is φ = 875542073532.

The previous prime is 1313313110281. The next prime is 1313313110309. The reversal of 1313313110301 is 1030113133131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1313313110301 - 2⁵ = 1313313110269 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313313110309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218885518381 + ... + 218885518386.

It is an arithmetic number, because the mean of its divisors is an integer number (437771036768).

Almost surely, 2^{1313313110301} is an apocalyptic number.

It is an amenable number.

1313313110301 is a deficient number, since it is larger than the sum of its proper divisors (437771036771).

1313313110301 is an equidigital number, since it uses as much as digits as its factorization.

1313313110301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437771036770.

The product of its (nonzero) digits is 243, while the sum is 21.

Adding to 1313313110301 its reverse (1030113133131), we get a palindrome (2343426243432).

The spelling of 1313313110301 in words is "one trillion, three hundred thirteen billion, three hundred thirteen million, one hundred ten thousand, three hundred one".