Base | Representation |
---|---|
bin | 10011000111001000001… |
… | …010111101100111111110 |
3 | 11122112220202120100222122 |
4 | 103013020022331213332 |
5 | 133004141233423314 |
6 | 2443155445042542 |
7 | 163612243135133 |
oct | 23071012754776 |
9 | 4575822510878 |
10 | 1313323342334 |
11 | 466a82874513 |
12 | 1926453b6452 |
13 | 96acc47a763 |
14 | 477cac4258a |
15 | 2426894728e |
hex | 131c82bd9fe |
1313323342334 has 4 divisors (see below), whose sum is σ = 1969985013504. Its totient is φ = 656661671166.
The previous prime is 1313323342333. The next prime is 1313323342343. The reversal of 1313323342334 is 4332433233131.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 1313323342294 and 1313323342303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1313323342333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 328330835582 + ... + 328330835585.
It is an arithmetic number, because the mean of its divisors is an integer number (492496253376).
Almost surely, 21313323342334 is an apocalyptic number.
1313323342334 is a deficient number, since it is larger than the sum of its proper divisors (656661671170).
1313323342334 is an equidigital number, since it uses as much as digits as its factorization.
1313323342334 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 656661671169.
The product of its digits is 139968, while the sum is 35.
Adding to 1313323342334 its reverse (4332433233131), we get a palindrome (5645756575465).
The spelling of 1313323342334 in words is "one trillion, three hundred thirteen billion, three hundred twenty-three million, three hundred forty-two thousand, three hundred thirty-four".
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