Base | Representation |
---|---|
bin | 11101110111001000110111… |
… | …101011111100101000110111 |
3 | 122020000020222211221010112110 |
4 | 131313020313223330220313 |
5 | 114203222321211311120 |
6 | 1143153143022222103 |
7 | 36443312254002312 |
oct | 3567106753745067 |
9 | 566006884833473 |
10 | 131332444244535 |
11 | 3893485aa45556 |
12 | 12891135a24933 |
13 | 583879a251b51 |
14 | 246074a64b979 |
15 | 102b3d19ad2e0 |
hex | 777237afca37 |
131332444244535 has 16 divisors (see below), whose sum is σ = 210242448401760. Its totient is φ = 70007124393600.
The previous prime is 131332444244503. The next prime is 131332444244627. The reversal of 131332444244535 is 535442444233131.
It is a happy number.
It is not a de Polignac number, because 131332444244535 - 25 = 131332444244503 is a prime.
It is a super-2 number, since 2×1313324442445352 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2302837420 + ... + 2302894449.
It is an arithmetic number, because the mean of its divisors is an integer number (13140153025110).
Almost surely, 2131332444244535 is an apocalyptic number.
131332444244535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
131332444244535 is a deficient number, since it is larger than the sum of its proper divisors (78910004157225).
131332444244535 is a wasteful number, since it uses less digits than its factorization.
131332444244535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4605733778.
The product of its digits is 8294400, while the sum is 48.
Adding to 131332444244535 its reverse (535442444233131), we get a palindrome (666774888477666).
The spelling of 131332444244535 in words is "one hundred thirty-one trillion, three hundred thirty-two billion, four hundred forty-four million, two hundred forty-four thousand, five hundred thirty-five".
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