131333000111 has 4 divisors (see below), whose sum is σ = 131338919424. Its totient is φ = 131327080800.

The previous prime is 131333000093. The next prime is 131333000137. The reversal of 131333000111 is 111000333131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111000333131 = 116411 ⋅953521.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131333000111 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131333000111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131333000171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2926250 + ... + 2970791.

It is an arithmetic number, because the mean of its divisors is an integer number (32834729856).

Almost surely, 2^131333000111 is an apocalyptic number.

131333000111 is a deficient number, since it is larger than the sum of its proper divisors (5919313).

131333000111 is an equidigital number, since it uses as much as digits as its factorization.

131333000111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5919312.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 131333000111 its reverse (111000333131), we get a palindrome (242333333242).

The spelling of 131333000111 in words is "one hundred thirty-one billion, three hundred thirty-three million, one hundred eleven", and thus it is an aban number.