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13133301131 is a prime number
BaseRepresentation
bin11000011101100111…
…00100010110001011
31020220021121211020102
430032303210112023
5203344111114011
610011112120015
7643312134446
oct141663442613
936807554212
1013133301131
11562a451585
12266639600b
131313ba4c02
148c834865d
1551ced373b
hex30ece458b

13133301131 has 2 divisors, whose sum is σ = 13133301132. Its totient is φ = 13133301130.

The previous prime is 13133301119. The next prime is 13133301143. The reversal of 13133301131 is 13110333131.

13133301131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (13133301119) and next prime (13133301143).

It is a cyclic number.

It is not a de Polignac number, because 13133301131 - 222 = 13129106827 is a prime.

It is a super-2 number, since 2×131333011312 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13133301161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566650565 + 6566650566.

It is an arithmetic number, because the mean of its divisors is an integer number (6566650566).

Almost surely, 213133301131 is an apocalyptic number.

13133301131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13133301131 is an equidigital number, since it uses as much as digits as its factorization.

13133301131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 20.

Adding to 13133301131 its reverse (13110333131), we get a palindrome (26243634262).

The spelling of 13133301131 in words is "thirteen billion, one hundred thirty-three million, three hundred one thousand, one hundred thirty-one".