Base | Representation |
---|---|
bin | 1011111100011101011001… |
… | …0001110101011000000101 |
3 | 1201111112100221211101002011 |
4 | 2333013112101311120011 |
5 | 3210134004331220143 |
6 | 43533205341014221 |
7 | 2523564444165154 |
oct | 277072621653005 |
9 | 51445327741064 |
10 | 13133310023173 |
11 | 420389513a26a |
12 | 15813a6b54371 |
13 | 743609541532 |
14 | 335926d5959b |
15 | 17b962dcce9d |
hex | bf1d6475605 |
13133310023173 has 2 divisors, whose sum is σ = 13133310023174. Its totient is φ = 13133310023172.
The previous prime is 13133310023111. The next prime is 13133310023219. The reversal of 13133310023173 is 37132001333131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11499918669409 + 1633391353764 = 3391153^2 + 1278042^2 .
It is a cyclic number.
It is not a de Polignac number, because 13133310023173 - 29 = 13133310022661 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13133310023773) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566655011586 + 6566655011587.
It is an arithmetic number, because the mean of its divisors is an integer number (6566655011587).
Almost surely, 213133310023173 is an apocalyptic number.
It is an amenable number.
13133310023173 is a deficient number, since it is larger than the sum of its proper divisors (1).
13133310023173 is an equidigital number, since it uses as much as digits as its factorization.
13133310023173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10206, while the sum is 31.
The spelling of 13133310023173 in words is "thirteen trillion, one hundred thirty-three billion, three hundred ten million, twenty-three thousand, one hundred seventy-three".
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