Base | Representation |
---|---|
bin | 11101110111001001100000… |
… | …101111110001011010110010 |
3 | 122020000022202212011021102200 |
4 | 131313021200233301122302 |
5 | 114203230224034104020 |
6 | 1143153335231124030 |
7 | 36443335320202233 |
oct | 3567114057613262 |
9 | 566008685137380 |
10 | 131333133113010 |
11 | 38935083881644 |
12 | 128912a8673616 |
13 | 5838879b9462a |
14 | 24607b3d2908a |
15 | 102b4221d2590 |
hex | 777260bf16b2 |
131333133113010 has 48 divisors (see below), whose sum is σ = 341466727357080. Its totient is φ = 35022109213440.
The previous prime is 131333133112997. The next prime is 131333133113029. The reversal of 131333133113010 is 10311331333131.
131333133113010 is a `hidden beast` number, since 1 + 3 + 1 + 3 + 3 + 313 + 311 + 30 + 1 + 0 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 93374090802729 + 37959042310281 = 9663027^2 + 6161091^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 85033536 + ... + 86564244.
Almost surely, 2131333133113010 is an apocalyptic number.
131333133113010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131333133113010 is an abundant number, since it is smaller than the sum of its proper divisors (210133594244070).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131333133113010 is a wasteful number, since it uses less digits than its factorization.
131333133113010 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2484043 (or 2484040 counting only the distinct ones).
The product of its (nonzero) digits is 2187, while the sum is 27.
Adding to 131333133113010 its reverse (10311331333131), we get a palindrome (141644464446141).
The spelling of 131333133113010 in words is "one hundred thirty-one trillion, three hundred thirty-three billion, one hundred thirty-three million, one hundred thirteen thousand, ten".
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