Base | Representation |
---|---|
bin | 10011000111001000110… |
… | …100000010110001101111 |
3 | 11122112221111211111021211 |
4 | 103013020310002301233 |
5 | 133004202013030333 |
6 | 2443200511535251 |
7 | 163612433516512 |
oct | 23071064026157 |
9 | 4575844744254 |
10 | 1313334111343 |
11 | 466a8895a421 |
12 | 192648b2a527 |
13 | 96b0177b357 |
14 | 477cc446d79 |
15 | 24269872ecd |
hex | 131c8d02c6f |
1313334111343 has 2 divisors, whose sum is σ = 1313334111344. Its totient is φ = 1313334111342.
The previous prime is 1313334111319. The next prime is 1313334111347. The reversal of 1313334111343 is 3431114333131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1313334111343 - 217 = 1313333980271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313334111347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656667055671 + 656667055672.
It is an arithmetic number, because the mean of its divisors is an integer number (656667055672).
Almost surely, 21313334111343 is an apocalyptic number.
1313334111343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313334111343 is an equidigital number, since it uses as much as digits as its factorization.
1313334111343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 11664, while the sum is 31.
Adding to 1313334111343 its reverse (3431114333131), we get a palindrome (4744448444474).
The spelling of 1313334111343 in words is "one trillion, three hundred thirteen billion, three hundred thirty-four million, one hundred eleven thousand, three hundred forty-three".
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