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131333555040071 is a prime number
BaseRepresentation
bin11101110111001001111001…
…111001010010111101000111
3122020000100212021002101112212
4131313021321321102331013
5114203232110042240241
61143153445142334035
736443351632420256
oct3567117171227507
9566010767071485
10131333555040071
113893527aa6369a
12128913a5a2a31b
135838916412507
142460813d9a79d
15102b449277beb
hex777279e52f47

131333555040071 has 2 divisors, whose sum is σ = 131333555040072. Its totient is φ = 131333555040070.

The previous prime is 131333555040007. The next prime is 131333555040073. The reversal of 131333555040071 is 170040555333131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131333555040071 - 26 = 131333555040007 is a prime.

It is a Sophie Germain prime.

Together with 131333555040073, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131333555040073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65666777520035 + 65666777520036.

It is an arithmetic number, because the mean of its divisors is an integer number (65666777520036).

Almost surely, 2131333555040071 is an apocalyptic number.

131333555040071 is a deficient number, since it is larger than the sum of its proper divisors (1).

131333555040071 is an equidigital number, since it uses as much as digits as its factorization.

131333555040071 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 283500, while the sum is 41.

The spelling of 131333555040071 in words is "one hundred thirty-one trillion, three hundred thirty-three billion, five hundred fifty-five million, forty thousand, seventy-one".