Base | Representation |
---|---|
bin | 10011000111001010101… |
… | …100001011110001111111 |
3 | 11122120000201002120011012 |
4 | 103013022230023301333 |
5 | 133004233043334003 |
6 | 2443203554545435 |
7 | 163613265310310 |
oct | 23071254136177 |
9 | 4576021076135 |
10 | 1313365605503 |
11 | 466aa4710456 |
12 | 19265759827b |
13 | 96b08157453 |
14 | 477d26c4607 |
15 | 2426c4e48d8 |
hex | 131cab0bc7f |
1313365605503 has 4 divisors (see below), whose sum is σ = 1500989263440. Its totient is φ = 1125741947568.
The previous prime is 1313365605479. The next prime is 1313365605533. The reversal of 1313365605503 is 3055065633131.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1313365605503 - 210 = 1313365604479 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1313365605533) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93811828958 + ... + 93811828971.
It is an arithmetic number, because the mean of its divisors is an integer number (375247315860).
Almost surely, 21313365605503 is an apocalyptic number.
1313365605503 is a deficient number, since it is larger than the sum of its proper divisors (187623657937).
1313365605503 is an equidigital number, since it uses as much as digits as its factorization.
1313365605503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 187623657936.
The product of its (nonzero) digits is 364500, while the sum is 41.
The spelling of 1313365605503 in words is "one trillion, three hundred thirteen billion, three hundred sixty-five million, six hundred five thousand, five hundred three".
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