Base | Representation |
---|---|
bin | 1011111100100000100100… |
… | …0111111011011100101101 |
3 | 1201111121120101222100221212 |
4 | 2333020021013323130231 |
5 | 3210142231221031441 |
6 | 43533430132404205 |
7 | 2523624543004364 |
oct | 277101107733455 |
9 | 51447511870855 |
10 | 13134163064621 |
11 | 42041927089a5 |
12 | 15815a4776665 |
13 | 7437141a5ca1 |
14 | 3359a83707db |
15 | 17b9b2c30eeb |
hex | bf2091fb72d |
13134163064621 has 4 divisors (see below), whose sum is σ = 13705213632672. Its totient is φ = 12563112496572.
The previous prime is 13134163064597. The next prime is 13134163064639. The reversal of 13134163064621 is 12646036143131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13134163064621 - 210 = 13134163063597 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13134163064651) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 285525283991 + ... + 285525284036.
It is an arithmetic number, because the mean of its divisors is an integer number (3426303408168).
Almost surely, 213134163064621 is an apocalyptic number.
It is an amenable number.
13134163064621 is a deficient number, since it is larger than the sum of its proper divisors (571050568051).
13134163064621 is an equidigital number, since it uses as much as digits as its factorization.
13134163064621 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 571050568050.
The product of its (nonzero) digits is 186624, while the sum is 41.
The spelling of 13134163064621 in words is "thirteen trillion, one hundred thirty-four billion, one hundred sixty-three million, sixty-four thousand, six hundred twenty-one".
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