Base | Representation |
---|---|
bin | 1011111100100000110100… |
… | …1000111100100010100111 |
3 | 1201111121202002202101202002 |
4 | 2333020031020330202213 |
5 | 3210142400443040403 |
6 | 43533440540435515 |
7 | 2523626321460353 |
oct | 277101510744247 |
9 | 51447662671662 |
10 | 13134230440103 |
11 | 4204217747113 |
12 | 1581603248b9b |
13 | 743725136036 |
14 | 3359b32ac463 |
15 | 17b9b8ade188 |
hex | bf20d23c8a7 |
13134230440103 has 2 divisors, whose sum is σ = 13134230440104. Its totient is φ = 13134230440102.
The previous prime is 13134230440087. The next prime is 13134230440181. The reversal of 13134230440103 is 30104403243131.
It is a happy number.
13134230440103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13134230440103 - 24 = 13134230440087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13134230440703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567115220051 + 6567115220052.
It is an arithmetic number, because the mean of its divisors is an integer number (6567115220052).
Almost surely, 213134230440103 is an apocalyptic number.
13134230440103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13134230440103 is an equidigital number, since it uses as much as digits as its factorization.
13134230440103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 13134230440103 its reverse (30104403243131), we get a palindrome (43238633683234).
The spelling of 13134230440103 in words is "thirteen trillion, one hundred thirty-four billion, two hundred thirty million, four hundred forty thousand, one hundred three".
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