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131342424014340 = 223257111725710692029
BaseRepresentation
bin11101110111010010001010…
…100001101111111000000100
3122020001012202100121222001100
4131313102022201233320010
5114203403241021424330
61143201513203300100
736444114464436150
oct3567221241577004
9566035670558040
10131342424014340
11389390112a22a0
121289306007a630
1358396ca9a8196
142461015c26060
15102b7b7bc2060
hex77748a86fe04

131342424014340 has 1152 divisors, whose sum is σ = 528732373478400. Its totient is φ = 25550043217920.

The previous prime is 131342424014287. The next prime is 131342424014359. The reversal of 131342424014340 is 43410424243131.

131342424014340 is a `hidden beast` number, since 1 + 3 + 1 + 3 + 4 + 242 + 401 + 4 + 3 + 4 + 0 = 666.

131342424014340 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a junction number, because it is equal to n+sod(n) for n = 131342424014295 and 131342424014304.

It is an unprimeable number.

It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 64732588446 + ... + 64732590474.

It is an arithmetic number, because the mean of its divisors is an integer number (458969074200).

Almost surely, 2131342424014340 is an apocalyptic number.

131342424014340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131342424014340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (264366186739200).

131342424014340 is an abundant number, since it is smaller than the sum of its proper divisors (397389949464060).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131342424014340 is a wasteful number, since it uses less digits than its factorization.

131342424014340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3405 (or 3400 counting only the distinct ones).

The product of its (nonzero) digits is 110592, while the sum is 36.

Adding to 131342424014340 its reverse (43410424243131), we get a palindrome (174752848257471).

The spelling of 131342424014340 in words is "one hundred thirty-one trillion, three hundred forty-two billion, four hundred twenty-four million, fourteen thousand, three hundred forty".