Base | Representation |
---|---|
bin | 11101110111010010111001… |
… | …011000001000110001000111 |
3 | 122020001021210010122101121111 |
4 | 131313102321120020301013 |
5 | 114203411343231232012 |
6 | 1143202123202225451 |
7 | 36444143120423422 |
oct | 3567227130106107 |
9 | 566037703571544 |
10 | 131343210024007 |
11 | 38939384a47a63 |
12 | 1289323b355287 |
13 | 58397c47a0167 |
14 | 246108c38c9b9 |
15 | 102b811bd3ba7 |
hex | 7774b9608c47 |
131343210024007 has 2 divisors, whose sum is σ = 131343210024008. Its totient is φ = 131343210024006.
The previous prime is 131343210023969. The next prime is 131343210024119. The reversal of 131343210024007 is 700420012343131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131343210024007 - 227 = 131343075806279 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131343210024007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131343210025007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65671605012003 + 65671605012004.
It is an arithmetic number, because the mean of its divisors is an integer number (65671605012004).
Almost surely, 2131343210024007 is an apocalyptic number.
131343210024007 is a deficient number, since it is larger than the sum of its proper divisors (1).
131343210024007 is an equidigital number, since it uses as much as digits as its factorization.
131343210024007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 131343210024007 its reverse (700420012343131), we get a palindrome (831763222367138).
The spelling of 131343210024007 in words is "one hundred thirty-one trillion, three hundred forty-three billion, two hundred ten million, twenty-four thousand, seven".
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