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131343210024119 is a prime number
BaseRepresentation
bin11101110111010010111001…
…011000001000110010110111
3122020001021210010122101202122
4131313102321120020302313
5114203411343231232434
61143202123202230155
736444143120423642
oct3567227130106267
9566037703571678
10131343210024119
1138939384a48055
121289323b35535b
1358397c47a0222
14246108c38ca59
15102b811bd3c2e
hex7774b9608cb7

131343210024119 has 2 divisors, whose sum is σ = 131343210024120. Its totient is φ = 131343210024118.

The previous prime is 131343210024007. The next prime is 131343210024139. The reversal of 131343210024119 is 911420012343131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131343210024119 is a prime.

It is a super-2 number, since 2×1313432100241192 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131343210024139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65671605012059 + 65671605012060.

It is an arithmetic number, because the mean of its divisors is an integer number (65671605012060).

Almost surely, 2131343210024119 is an apocalyptic number.

131343210024119 is a deficient number, since it is larger than the sum of its proper divisors (1).

131343210024119 is an equidigital number, since it uses as much as digits as its factorization.

131343210024119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 131343210024119 in words is "one hundred thirty-one trillion, three hundred forty-three billion, two hundred ten million, twenty-four thousand, one hundred nineteen".