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1313433376397 is a prime number
BaseRepresentation
bin10011000111001110101…
…110101101011010001101
311122120012102121200100022
4103013032232231122031
5133004402421021042
62443214415311525
7163615050331142
oct23071656553215
94576172550308
101313433376397
1146702999975a
1219267621b5a5
1396b191c547c
14477db6c63c9
152427342ecd2
hex131cebad68d

1313433376397 has 2 divisors, whose sum is σ = 1313433376398. Its totient is φ = 1313433376396.

The previous prime is 1313433376391. The next prime is 1313433376439. The reversal of 1313433376397 is 7936733343131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 817470947881 + 495962428516 = 904141^2 + 704246^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313433376397 - 214 = 1313433360013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313433376391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656716688198 + 656716688199.

It is an arithmetic number, because the mean of its divisors is an integer number (656716688199).

Almost surely, 21313433376397 is an apocalyptic number.

It is an amenable number.

1313433376397 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313433376397 is an equidigital number, since it uses as much as digits as its factorization.

1313433376397 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7715736, while the sum is 53.

The spelling of 1313433376397 in words is "one trillion, three hundred thirteen billion, four hundred thirty-three million, three hundred seventy-six thousand, three hundred ninety-seven".