Base | Representation |
---|---|
bin | 11000011101101111… |
… | …11000101101011011 |
3 | 1020220100202100000202 |
4 | 30032313320231123 |
5 | 203344403324430 |
6 | 10011152252415 |
7 | 643324560626 |
oct | 141667705533 |
9 | 36810670022 |
10 | 13134433115 |
11 | 5630055001 |
12 | 266684110b |
13 | 13141b021b |
14 | 8c8560dbd |
15 | 51d158d45 |
hex | 30edf8b5b |
13134433115 has 8 divisors (see below), whose sum is σ = 15796425600. Its totient is φ = 10484142592.
The previous prime is 13134433003. The next prime is 13134433127. The reversal of 13134433115 is 51133443131.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13134433115 - 28 = 13134432859 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2923019 + ... + 2927508.
It is an arithmetic number, because the mean of its divisors is an integer number (1974553200).
Almost surely, 213134433115 is an apocalyptic number.
13134433115 is a deficient number, since it is larger than the sum of its proper divisors (2661992485).
13134433115 is an equidigital number, since it uses as much as digits as its factorization.
13134433115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5850981.
The product of its digits is 6480, while the sum is 29.
Adding to 13134433115 its reverse (51133443131), we get a palindrome (64267876246).
The spelling of 13134433115 in words is "thirteen billion, one hundred thirty-four million, four hundred thirty-three thousand, one hundred fifteen".
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