Base | Representation |
---|---|
bin | 1011111100100001101000… |
… | …1110111101110110100110 |
3 | 1201111122022102010101212012 |
4 | 2333020122032331312212 |
5 | 3210143323212402100 |
6 | 43533514425154222 |
7 | 2523634626650660 |
oct | 277103216756646 |
9 | 51448272111765 |
10 | 13134450122150 |
11 | 420431a752525 |
12 | 158166492b972 |
13 | 74375b7c1b06 |
14 | 3359d4535530 |
15 | 17b9cd035135 |
hex | bf21a3bdda6 |
13134450122150 has 48 divisors (see below), whose sum is σ = 27920565990240. Its totient is φ = 4503162988800.
The previous prime is 13134450122141. The next prime is 13134450122197. The reversal of 13134450122150 is 5122105443131.
It is a super-2 number, since 2×131344501221502 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 22471610 + ... + 23048690.
It is an arithmetic number, because the mean of its divisors is an integer number (581678458130).
Almost surely, 213134450122150 is an apocalyptic number.
13134450122150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13134450122150 is an abundant number, since it is smaller than the sum of its proper divisors (14786115868090).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13134450122150 is a wasteful number, since it uses less digits than its factorization.
13134450122150 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 642129 (or 642124 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 13134450122150 its reverse (5122105443131), we get a palindrome (18256555565281).
The spelling of 13134450122150 in words is "thirteen trillion, one hundred thirty-four billion, four hundred fifty million, one hundred twenty-two thousand, one hundred fifty".
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