Base | Representation |
---|---|
bin | 10011000111001111011… |
… | …111000101000100111101 |
3 | 11122120020022110212211121 |
4 | 103013033133011010331 |
5 | 133004414142300003 |
6 | 2443215551150541 |
7 | 163615263161512 |
oct | 23071737050475 |
9 | 4576208425747 |
10 | 1313446056253 |
11 | 46703606a281 |
12 | 19267a515451 |
13 | 96b1ba14a46 |
14 | 477dd267309 |
15 | 242745d6cbd |
hex | 131cf7c513d |
1313446056253 has 2 divisors, whose sum is σ = 1313446056254. Its totient is φ = 1313446056252.
The previous prime is 1313446056239. The next prime is 1313446056319. The reversal of 1313446056253 is 3526506443131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1289864461284 + 23581594969 = 1135722^2 + 153563^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1313446056253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313446056653) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656723028126 + 656723028127.
It is an arithmetic number, because the mean of its divisors is an integer number (656723028127).
Almost surely, 21313446056253 is an apocalyptic number.
It is an amenable number.
1313446056253 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313446056253 is an equidigital number, since it uses as much as digits as its factorization.
1313446056253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 777600, while the sum is 43.
The spelling of 1313446056253 in words is "one trillion, three hundred thirteen billion, four hundred forty-six million, fifty-six thousand, two hundred fifty-three".
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