Base | Representation |
---|---|
bin | 11101110111010100111001… |
… | …000011010101010101100011 |
3 | 122020001111022102020210111221 |
4 | 131313110321003111111203 |
5 | 114203430240111212430 |
6 | 1143203115521315511 |
7 | 36444250160402233 |
oct | 3567247103252543 |
9 | 566044272223457 |
10 | 131345352054115 |
11 | 3893a284082981 |
12 | 12893738795b97 |
13 | 5839a764b58b4 |
14 | 2461212a59cc3 |
15 | 102b8d9c9e57a |
hex | 7775390d5563 |
131345352054115 has 8 divisors (see below), whose sum is σ = 157930283034000. Its totient is φ = 104865707930592.
The previous prime is 131345352054017. The next prime is 131345352054187. The reversal of 131345352054115 is 511450253543131.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131345352054115 - 211 = 131345352052067 is a prime.
It is a super-2 number, since 2×1313453520541152 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26321711344 + ... + 26321716333.
It is an arithmetic number, because the mean of its divisors is an integer number (19741285379250).
Almost surely, 2131345352054115 is an apocalyptic number.
131345352054115 is a deficient number, since it is larger than the sum of its proper divisors (26584930979885).
131345352054115 is an equidigital number, since it uses as much as digits as its factorization.
131345352054115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52643428181.
The product of its (nonzero) digits is 540000, while the sum is 43.
The spelling of 131345352054115 in words is "one hundred thirty-one trillion, three hundred forty-five billion, three hundred fifty-two million, fifty-four thousand, one hundred fifteen".
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