131350350241535 has 4 divisors (see below), whose sum is σ = 157620420289848. Its totient is φ = 105080280193224.

The previous prime is 131350350241477. The next prime is 131350350241541. The reversal of 131350350241535 is 535142053053131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131350350241535 - 2¹⁴ = 131350350225151 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131350350241492 and 131350350241501.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13135035024149 + ... + 13135035024158.

It is an arithmetic number, because the mean of its divisors is an integer number (39405105072462).

Almost surely, 2^{131350350241535} is an apocalyptic number.

131350350241535 is a deficient number, since it is larger than the sum of its proper divisors (26270070048313).

131350350241535 is an equidigital number, since it uses as much as digits as its factorization.

131350350241535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26270070048312.

The product of its (nonzero) digits is 405000, while the sum is 41.

The spelling of 131350350241535 in words is "one hundred thirty-one trillion, three hundred fifty billion, three hundred fifty million, two hundred forty-one thousand, five hundred thirty-five".