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131350423524055 = 5177954271942729
BaseRepresentation
bin11101110111011001100111…
…010101011101001011010111
3122020001222101212010011101221
4131313121213111131023113
5114204021131410232210
61143205315044431211
736444516641235001
oct3567314725351327
9566058355104357
10131350423524055
113894144686534a
12128947130a8507
13583a3a40a9098
142461574403371
15102bad51221da
hex77766755d2d7

131350423524055 has 16 divisors (see below), whose sum is σ = 166892598551520. Its totient is φ = 98898967176192.

The previous prime is 131350423523993. The next prime is 131350423524077. The reversal of 131350423524055 is 550425324053131.

It is a cyclic number.

It is not a de Polignac number, because 131350423524055 - 213 = 131350423515863 is a prime.

It is a super-2 number, since 2×1313504235240552 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 66639931 + ... + 68582659.

It is an arithmetic number, because the mean of its divisors is an integer number (10430787409470).

Almost surely, 2131350423524055 is an apocalyptic number.

131350423524055 is a deficient number, since it is larger than the sum of its proper divisors (35542175027465).

131350423524055 is a wasteful number, since it uses less digits than its factorization.

131350423524055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2738178.

The product of its (nonzero) digits is 1080000, while the sum is 43.

Adding to 131350423524055 its reverse (550425324053131), we get a palindrome (681775747577186).

The spelling of 131350423524055 in words is "one hundred thirty-one trillion, three hundred fifty billion, four hundred twenty-three million, five hundred twenty-four thousand, fifty-five".

Divisors: 1 5 17 85 795427 1942729 3977135 9713645 13522259 33026393 67611295 165131965 1545299100283 7726495501415 26270084704811 131350423524055