Base | Representation |
---|---|
bin | 11101110111011001100111… |
… | …010101011101001011010111 |
3 | 122020001222101212010011101221 |
4 | 131313121213111131023113 |
5 | 114204021131410232210 |
6 | 1143205315044431211 |
7 | 36444516641235001 |
oct | 3567314725351327 |
9 | 566058355104357 |
10 | 131350423524055 |
11 | 3894144686534a |
12 | 128947130a8507 |
13 | 583a3a40a9098 |
14 | 2461574403371 |
15 | 102bad51221da |
hex | 77766755d2d7 |
131350423524055 has 16 divisors (see below), whose sum is σ = 166892598551520. Its totient is φ = 98898967176192.
The previous prime is 131350423523993. The next prime is 131350423524077. The reversal of 131350423524055 is 550425324053131.
It is a cyclic number.
It is not a de Polignac number, because 131350423524055 - 213 = 131350423515863 is a prime.
It is a super-2 number, since 2×1313504235240552 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 66639931 + ... + 68582659.
It is an arithmetic number, because the mean of its divisors is an integer number (10430787409470).
Almost surely, 2131350423524055 is an apocalyptic number.
131350423524055 is a deficient number, since it is larger than the sum of its proper divisors (35542175027465).
131350423524055 is a wasteful number, since it uses less digits than its factorization.
131350423524055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2738178.
The product of its (nonzero) digits is 1080000, while the sum is 43.
Adding to 131350423524055 its reverse (550425324053131), we get a palindrome (681775747577186).
The spelling of 131350423524055 in words is "one hundred thirty-one trillion, three hundred fifty billion, four hundred twenty-three million, five hundred twenty-four thousand, fifty-five".
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