Base | Representation |
---|---|
bin | 11101110111011001101101… |
… | …111100100101010000010010 |
3 | 122020001222200120211111000220 |
4 | 131313121231330211100102 |
5 | 114204021343304202200 |
6 | 1143205334050053510 |
7 | 36444522456110625 |
oct | 3567315574452022 |
9 | 566058616744026 |
10 | 131350534444050 |
11 | 389414a3435169 |
12 | 1289474427a296 |
13 | 583a3c107410c |
14 | 2461585037dbc |
15 | 102badec324a0 |
hex | 77766df25412 |
131350534444050 has 48 divisors (see below), whose sum is σ = 325894945084992. Its totient is φ = 35011151156800.
The previous prime is 131350534444039. The next prime is 131350534444109. The reversal of 131350534444050 is 50444435053131.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 131350534443993 and 131350534444011.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 195388686 + ... + 196059785.
It is an arithmetic number, because the mean of its divisors is an integer number (6789478022604).
Almost surely, 2131350534444050 is an apocalyptic number.
131350534444050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131350534444050 is an abundant number, since it is smaller than the sum of its proper divisors (194544410640942).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131350534444050 is a wasteful number, since it uses less digits than its factorization.
131350534444050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 391450723 (or 391450718 counting only the distinct ones).
The product of its (nonzero) digits is 864000, while the sum is 42.
Adding to 131350534444050 its reverse (50444435053131), we get a palindrome (181794969497181).
The spelling of 131350534444050 in words is "one hundred thirty-one trillion, three hundred fifty billion, five hundred thirty-four million, four hundred forty-four thousand, fifty".
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