Base | Representation |
---|---|
bin | 1011111100100100011111… |
… | …1000101101110010111111 |
3 | 1201111201021210100010012121 |
4 | 2333021013320231302333 |
5 | 3210201410301304101 |
6 | 43534122425343411 |
7 | 2523662620110661 |
oct | 277110770556277 |
9 | 51451253303177 |
10 | 13135216041151 |
11 | 4204683025836 |
12 | 1581839337b67 |
13 | 7438513a1319 |
14 | 335a6814c531 |
15 | 17ba253c90a1 |
hex | bf247e2dcbf |
13135216041151 has 4 divisors (see below), whose sum is σ = 13207786295704. Its totient is φ = 13062645786600.
The previous prime is 13135216041149. The next prime is 13135216041173. The reversal of 13135216041151 is 15114061253131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13135216041151 - 21 = 13135216041149 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13135216051151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36285127005 + ... + 36285127366.
It is an arithmetic number, because the mean of its divisors is an integer number (3301946573926).
Almost surely, 213135216041151 is an apocalyptic number.
13135216041151 is a deficient number, since it is larger than the sum of its proper divisors (72570254553).
13135216041151 is an equidigital number, since it uses as much as digits as its factorization.
13135216041151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72570254552.
The product of its (nonzero) digits is 10800, while the sum is 34.
Adding to 13135216041151 its reverse (15114061253131), we get a palindrome (28249277294282).
The spelling of 13135216041151 in words is "thirteen trillion, one hundred thirty-five billion, two hundred sixteen million, forty-one thousand, one hundred fifty-one".
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