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131352427693 = 293448301801
BaseRepresentation
bin111101001010100110…
…1101111110010101101
3110120001011202200122101
41322111031233302231
54123002210141233
6140201550215101
712330015133144
oct1722515576255
9416034680571
10131352427693
1150785026073
12215597b4491
13c504137bc6
146500d5675b
15363b95cc7d
hex1e9536fcad

131352427693 has 4 divisors (see below), whose sum is σ = 131800729788. Its totient is φ = 130904125600.

The previous prime is 131352427651. The next prime is 131352427721. The reversal of 131352427693 is 396724253131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 90323089444 + 41029338249 = 300538^2 + 202557^2 .

It is a cyclic number.

It is not a de Polignac number, because 131352427693 - 213 = 131352419501 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131352427643) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224150608 + ... + 224151193.

It is an arithmetic number, because the mean of its divisors is an integer number (32950182447).

Almost surely, 2131352427693 is an apocalyptic number.

It is an amenable number.

131352427693 is a deficient number, since it is larger than the sum of its proper divisors (448302095).

131352427693 is an equidigital number, since it uses as much as digits as its factorization.

131352427693 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 448302094.

The product of its digits is 816480, while the sum is 46.

The spelling of 131352427693 in words is "one hundred thirty-one billion, three hundred fifty-two million, four hundred twenty-seven thousand, six hundred ninety-three".

Divisors: 1 293 448301801 131352427693