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13135303101 = 34378434367
BaseRepresentation
bin11000011101110110…
…01101000110111101
31020220102101112102110
430032323031012331
5203400114144401
610011223044233
7643335143214
oct141673150675
936812345373
1013135303101
1156305996a8
122666ba0679
1313144261cb
148c870a07b
1551d27b9d6
hex30eecd1bd

13135303101 has 4 divisors (see below), whose sum is σ = 17513737472. Its totient is φ = 8756868732.

The previous prime is 13135303091. The next prime is 13135303121. The reversal of 13135303101 is 10130353131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10130353131 = 33376784377.

It is not a de Polignac number, because 13135303101 - 215 = 13135270333 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13135303121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2189217181 + ... + 2189217186.

It is an arithmetic number, because the mean of its divisors is an integer number (4378434368).

Almost surely, 213135303101 is an apocalyptic number.

It is an amenable number.

13135303101 is a deficient number, since it is larger than the sum of its proper divisors (4378434371).

13135303101 is an equidigital number, since it uses as much as digits as its factorization.

13135303101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4378434370.

The product of its (nonzero) digits is 405, while the sum is 21.

Adding to 13135303101 its reverse (10130353131), we get a palindrome (23265656232).

The spelling of 13135303101 in words is "thirteen billion, one hundred thirty-five million, three hundred three thousand, one hundred one".

Divisors: 1 3 4378434367 13135303101