1313563450181 has 2 divisors, whose sum is σ = 1313563450182. Its totient is φ = 1313563450180.

The previous prime is 1313563450021. The next prime is 1313563450193. The reversal of 1313563450181 is 1810543653131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 689082612100 + 624480838081 = 830110^2 + 790241^2 .

It is an emirp because it is prime and its reverse (1810543653131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1313563450181 is a prime.

It is a super-3 number, since 3×1313563450181³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313563450481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656781725090 + 656781725091.

It is an arithmetic number, because the mean of its divisors is an integer number (656781725091).

Almost surely, 2^{1313563450181} is an apocalyptic number.

It is an amenable number.

1313563450181 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313563450181 is an equidigital number, since it uses as much as digits as its factorization.

1313563450181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 129600, while the sum is 41.

The spelling of 1313563450181 in words is "one trillion, three hundred thirteen billion, five hundred sixty-three million, four hundred fifty thousand, one hundred eighty-one".